यदि \(f:\mathbb{R}\to\mathbb{R}\) और (f(x)=\frac{x}{1+x-2}), तो (f(2)+f\left\(\frac{1}{2}\right\)) का मान क्या है?

If \(f:\mathbb{R}\to\mathbb{R}\) and (f(x)=\frac{x}{1+x-2}), what is the value of (f(2)+f\left\(\frac{1}{2}\right\))?

Explanation opens after your attempt
Correct Answer

B. \(\frac{4}{5}\)

Step 1

Concept

(f(2)=\frac{2}{1+4}=\frac{2}{5}).

Step 2

Why this answer is correct

(f\left\(\frac{1}{2}\right\)=\frac{\frac{1}{2}}{1+\frac{1}{4}}=\frac{2}{5}).

Step 3

Exam Tip

Adding them gives \(\frac{4}{5}\). चरण 1: (f(2)=\frac{2}{1+4}=\frac{2}{5})। चरण 2: (f\left\(\frac{1}{2}\right\)=\frac{\frac{1}{2}}{1+\frac{1}{4}}=\frac{2}{5})। चरण 3: दोनों को जोड़ने पर \(\frac{4}{5}\) मिलता है।

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यदि \(f:\mathbb{R}\to\mathbb{R}\) और (f(x)=\frac{x}{1+x-2}), तो (f(2)+f\left\(\frac{1}{2}\right\)) का मान क्या है? / If \(f:\mathbb{R}\to\mathbb{R}\) and (f(x)=\frac{x}{1+x-2}), what is the value of (f(2)+f\left\(\frac{1}{2}\right\))?

Correct Answer: B. \(\frac{4}{5}\). Explanation: चरण 1: (f(2)=\frac{2}{1+4}=\frac{2}{5})। चरण 2: (f\left\(\frac{1}{2}\right\)=\frac{\frac{1}{2}}{1+\frac{1}{4}}=\frac{2}{5})। चरण 3: दोनों को जोड़ने पर \(\frac{4}{5}\) मिलता है। / Step 1: (f(2)=\frac{2}{1+4}=\frac{2}{5}). Step 2: (f\left\(\frac{1}{2}\right\)=\frac{\frac{1}{2}}{1+\frac{1}{4}}=\frac{2}{5}). Step 3: Adding them gives \(\frac{4}{5}\).

Which concept should I revise for this Mathematics MCQ?

(f(2)=\frac{2}{1+4}=\frac{2}{5}).

What exam hint can help solve this Mathematics question?

Adding them gives \(\frac{4}{5}\). चरण 1: (f(2)=\frac{2}{1+4}=\frac{2}{5})। चरण 2: (f\left\(\frac{1}{2}\right\)=\frac{\frac{1}{2}}{1+\frac{1}{4}}=\frac{2}{5})। चरण 3: दोनों को जोड़ने पर \(\frac{4}{5}\) मिलता है।