\(संबंध (R={(x,y):x-y\) विषम है\(}), जहाँ (x,y\in {1,2,3,4}), के लिए सही कथन कौन-सा है\)?
\(For the relation (R={(x,y):x-y\) is odd\(}), where (x,y\in {1,2,3,4}), which statement is correct\)?
Explanation opens after your attempt
Correct Answer
A. सममित हैIt is symmetric
Concept
If (x-y) is odd, then (y-x=-(x-y)) is also odd.
Why this answer is correct
Hence whenever ((x,y)) is in the relation, ((y,x)) will also be in it.
Exam Tip
In difference-based parity rules, changing the sign does not change oddness or evenness. चरण 1: यदि (x-y) विषम है, तो (y-x=-(x-y)) भी विषम होगा। चरण 2: इसलिए ((x,y)) होने पर ((y,x)) भी संबंध में होगा। चरण 3: अंतर वाले नियम में चिन्ह बदलने से सम या विषम होने की प्रकृति नहीं बदलती।
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