असमानता \(|3x-4|\ge 11\) संख्या रेखा पर किस interval से दर्शाई जाएगी?
Which interval represents \(|3x-4|\ge 11\) on the number line?
Explanation opens after your attempt
Correct Answer
B. (\(-\infty,-\frac{7}{3}]\cup[5,\infty\))
Concept
\(|3x-4|\ge11\) gives \(3x-4\le-11\) or \(3x-4\ge11\), so \(x\le-\frac{7}{3}\) or \(x\ge5\). In exams, modulus with \(\ge\) gives closed outer rays.
Why this answer is correct
The correct answer is B. (\(-\infty,-\frac{7}{3}]\cup[5,\infty\)). \(|3x-4|\ge11\) gives \(3x-4\le-11\) or \(3x-4\ge11\), so \(x\le-\frac{7}{3}\) or \(x\ge5\). In exams, modulus with \(\ge\) gives closed outer rays.
Exam Tip
\(|3x-4|\ge11\) से \(3x-4\le-11\) या \(3x-4\ge11\), इसलिए \(x\le-\frac{7}{3}\) या \(x\ge5\)। परीक्षा में \(\ge\) वाले modulus में बाहर के closed rays बनते हैं।
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