असमानता \(y\leq -2x+6\) में बिंदु ( (1,3) ) कहाँ है?

Where is the point ( (1,3) ) for \(y\leq -2x+6\)?

Explanation opens after your attempt
Correct Answer

A. हल क्षेत्र मेंin solution region

Step 1

Concept

(3\leq -2(1)+6), i.e. \(3\leq 4\), is true. So it is in the solution region.

Step 2

Why this answer is correct

The correct answer is A. हल क्षेत्र में / in solution region. (3\leq -2(1)+6), i.e. \(3\leq 4\), is true. So it is in the solution region.

Step 3

Exam Tip

(3\leq -2(1)+6) यानी \(3\leq 4\) सत्य है। इसलिए यह हल क्षेत्र में है।

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Mathematics Answer, Explanation and Revision Hints

असमानता \(y\leq -2x+6\) में बिंदु ( (1,3) ) कहाँ है? / Where is the point ( (1,3) ) for \(y\leq -2x+6\)?

Correct Answer: A. हल क्षेत्र में / in solution region. Explanation: (3\leq -2(1)+6) यानी \(3\leq 4\) सत्य है। इसलिए यह हल क्षेत्र में है। / (3\leq -2(1)+6), i.e. \(3\leq 4\), is true. So it is in the solution region.

Which concept should I revise for this Mathematics MCQ?

(3\leq -2(1)+6), i.e. \(3\leq 4\), is true. So it is in the solution region.

What exam hint can help solve this Mathematics question?

(3\leq -2(1)+6) यानी \(3\leq 4\) सत्य है। इसलिए यह हल क्षेत्र में है।