फलन (f(x)=\frac{1}{\sqrt{x-2}}) का प्रांत क्या होगा?

What will be the domain of (f(x)=\frac{1}{\sqrt{x-2}})?

Explanation opens after your attempt
Correct Answer

A. (x>2)

Step 1

Concept

The square root is in the denominator, so (x-2>0) is required. Hence the domain is (\(2,\infty\)).

Step 2

Why this answer is correct

The correct answer is A. (x>2). The square root is in the denominator, so (x-2>0) is required. Hence the domain is (\(2,\infty\)).

Step 3

Exam Tip

हर में वर्गमूल है, इसलिए (x-2>0) चाहिए। इसलिए प्रांत (\(2,\infty\)) है।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{1}{\sqrt{x-2}}) का प्रांत क्या होगा? / What will be the domain of (f(x)=\frac{1}{\sqrt{x-2}})?

Correct Answer: A. (x>2). Explanation: हर में वर्गमूल है, इसलिए (x-2>0) चाहिए। इसलिए प्रांत (\(2,\infty\)) है। / The square root is in the denominator, so (x-2>0) is required. Hence the domain is (\(2,\infty\)).

Which concept should I revise for this Mathematics MCQ?

The square root is in the denominator, so (x-2>0) is required. Hence the domain is (\(2,\infty\)).

What exam hint can help solve this Mathematics question?

हर में वर्गमूल है, इसलिए (x-2>0) चाहिए। इसलिए प्रांत (\(2,\infty\)) है।