ग्राफ \(y=x^2-6x+11\) का शीर्ष बिंदु कौन सा है?

What is the vertex of the graph \(y=x^2-6x+11\)?

Explanation opens after your attempt
Correct Answer

A. ( \left\(3,2\right\) )

Step 1

Concept

Completing the square gives (y=(x-3)2+2). Therefore the vertex is (\left\(3,2\right\)).

Step 2

Why this answer is correct

The correct answer is A. ( \left\(3,2\right\) ). Completing the square gives (y=(x-3)2+2). Therefore the vertex is (\left\(3,2\right\)).

Step 3

Exam Tip

पूर्ण वर्ग बनाने पर (y=(x-3)2+2) मिलता है। इसलिए शीर्ष (\left\(3,2\right\)) है।

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Mathematics Answer, Explanation and Revision Hints

ग्राफ \(y=x^2-6x+11\) का शीर्ष बिंदु कौन सा है? / What is the vertex of the graph \(y=x^2-6x+11\)?

Correct Answer: A. ( \left\(3,2\right\) ). Explanation: पूर्ण वर्ग बनाने पर (y=(x-3)2+2) मिलता है। इसलिए शीर्ष (\left\(3,2\right\)) है। / Completing the square gives (y=(x-3)2+2). Therefore the vertex is (\left\(3,2\right\)).

Which concept should I revise for this Mathematics MCQ?

Completing the square gives (y=(x-3)2+2). Therefore the vertex is (\left\(3,2\right\)).

What exam hint can help solve this Mathematics question?

पूर्ण वर्ग बनाने पर (y=(x-3)2+2) मिलता है। इसलिए शीर्ष (\left\(3,2\right\)) है।