संबंध \(R=\{(x,y):y=\frac{x+1}{x-2},\ x\in{0,1,3,4},\ y\in\mathbb{R}\}\) का परिसर क्या है?

What is the range of \(R=\{(x,y):y=\frac{x+1}{x-2},\ x\in{0,1,3,4},\ y\in\mathbb{R}\}\)?

Explanation opens after your attempt
Correct Answer

A. \(\left{-\frac{1}{2},-2,4,\frac{5}{2}\right}\)

Step 1

Concept

At the given inputs, the values are \(-\frac{1}{2},-2,4,\frac{5}{2}\). For a finite domain, substitute directly.

Step 2

Why this answer is correct

The correct answer is A. \(\left{-\frac{1}{2},-2,4,\frac{5}{2}\right}\). At the given inputs, the values are \(-\frac{1}{2},-2,4,\frac{5}{2}\). For a finite domain, substitute directly.

Step 3

Exam Tip

दिए गए इनपुटों पर मान \(-\frac{1}{2},-2,4,\frac{5}{2}\) मिलते हैं। सीमित प्रांत में सीधे प्रतिस्थापन करें।

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Mathematics Answer, Explanation and Revision Hints

संबंध \(R=\{(x,y):y=\frac{x+1}{x-2},\ x\in{0,1,3,4},\ y\in\mathbb{R}\}\) का परिसर क्या है? / What is the range of \(R=\{(x,y):y=\frac{x+1}{x-2},\ x\in{0,1,3,4},\ y\in\mathbb{R}\}\)?

Correct Answer: A. \(\left{-\frac{1}{2},-2,4,\frac{5}{2}\right}\). Explanation: दिए गए इनपुटों पर मान \(-\frac{1}{2},-2,4,\frac{5}{2}\) मिलते हैं। सीमित प्रांत में सीधे प्रतिस्थापन करें। / At the given inputs, the values are \(-\frac{1}{2},-2,4,\frac{5}{2}\). For a finite domain, substitute directly.

Which concept should I revise for this Mathematics MCQ?

At the given inputs, the values are \(-\frac{1}{2},-2,4,\frac{5}{2}\). For a finite domain, substitute directly.

What exam hint can help solve this Mathematics question?

दिए गए इनपुटों पर मान \(-\frac{1}{2},-2,4,\frac{5}{2}\) मिलते हैं। सीमित प्रांत में सीधे प्रतिस्थापन करें।