फलन (f(x)=\frac{x-2}{x-2-4}) का परिसर क्या है?
What is the range of (f(x)=\frac{x-2}{x-2-4})?
Explanation opens after your attempt
Correct Answer
A. ( (-\infty,0]\cup\(1,\infty\) )
Concept
Put \(t=x^2\ge 0\) and \(t\ne 4\). Then \(f=\frac{t}{t-4}\), giving (\(-\infty,0]\) for \(t\in[0,4\)) and (\(1,\infty\)) for (t>4).
Why this answer is correct
The correct answer is A. ( (-\infty,0]\cup\(1,\infty\) ). Put \(t=x^2\ge 0\) and \(t\ne 4\). Then \(f=\frac{t}{t-4}\), giving (\(-\infty,0]\) for \(t\in[0,4\)) and (\(1,\infty\)) for (t>4).
Exam Tip
मान \(t=x^2\ge 0\) रखें और \(t\ne 4\)। तब \(f=\frac{t}{t-4}\), जिससे \(t\in[0,4\)) पर (\(-\infty,0]\) और (t>4) पर (\(1,\infty\)) मिलता है।
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