फलन (f(x)=\frac{1}{x-2-6x+10}) का अधिकतम मान क्या है?

What is the maximum value of (f(x)=\frac{1}{x-2-6x+10})?

Explanation opens after your attempt
Correct Answer

A. (1)

Step 1

Concept

The denominator (x-2-6x+10=(x-3)2+1) has minimum (1). Therefore the maximum fraction is (1).

Step 2

Why this answer is correct

The correct answer is A. (1). The denominator (x-2-6x+10=(x-3)2+1) has minimum (1). Therefore the maximum fraction is (1).

Step 3

Exam Tip

हर (x-2-6x+10=(x-3)2+1) का न्यूनतम (1) है। इसलिए भिन्न का अधिकतम (1) होगा।

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Mathematics Answer, Explanation and Revision Hints

फलन (f(x)=\frac{1}{x-2-6x+10}) का अधिकतम मान क्या है? / What is the maximum value of (f(x)=\frac{1}{x-2-6x+10})?

Correct Answer: A. (1). Explanation: हर (x-2-6x+10=(x-3)2+1) का न्यूनतम (1) है। इसलिए भिन्न का अधिकतम (1) होगा। / The denominator (x-2-6x+10=(x-3)2+1) has minimum (1). Therefore the maximum fraction is (1).

Which concept should I revise for this Mathematics MCQ?

The denominator (x-2-6x+10=(x-3)2+1) has minimum (1). Therefore the maximum fraction is (1).

What exam hint can help solve this Mathematics question?

हर (x-2-6x+10=(x-3)2+1) का न्यूनतम (1) है। इसलिए भिन्न का अधिकतम (1) होगा।