फलन (f(x)=\frac{1}{x-2-6x+10}) का अधिकतम मान क्या है?
What is the maximum value of (f(x)=\frac{1}{x-2-6x+10})?
Explanation opens after your attempt
A. (1)
Concept
The denominator (x-2-6x+10=(x-3)2+1) has minimum (1). Therefore the maximum fraction is (1).
Why this answer is correct
The correct answer is A. (1). The denominator (x-2-6x+10=(x-3)2+1) has minimum (1). Therefore the maximum fraction is (1).
Exam Tip
हर (x-2-6x+10=(x-3)2+1) का न्यूनतम (1) है। इसलिए भिन्न का अधिकतम (1) होगा।
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