फलन (f(x)=\sqrt{x-2-1}) का प्रांत क्या है?
What is the domain of (f(x)=\sqrt{x-2-1})?
Explanation opens after your attempt
Correct Answer
A. ( \(-\infty,-1]\cup[1,\infty\) )
Concept
The square root needs \(x^2-1\ge 0\). Thus \(|x|\ge 1\), so \(x\le -1\) or \(x\ge 1\).
Why this answer is correct
The correct answer is A. ( \(-\infty,-1]\cup[1,\infty\) ). The square root needs \(x^2-1\ge 0\). Thus \(|x|\ge 1\), so \(x\le -1\) or \(x\ge 1\).
Exam Tip
वर्गमूल के लिए \(x^2-1\ge 0\) चाहिए। इसलिए \(|x|\ge 1\), यानी \(x\le -1\) या \(x\ge 1\)।
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