फलन (f(x)=\sqrt{\frac{x-2}{x+1}}) का डोमेन क्या है?
What is the domain of (f(x)=\sqrt{\frac{x-2}{x+1}})?
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,-1\)\cup[2,\infty))
Concept
The expression inside the square root must satisfy \(\frac{x-2}{x+1}\ge 0\) and \(x\ne -1\). A sign table gives (\(-\infty,-1\)\cup[2,\infty)).
Why this answer is correct
The correct answer is A. (\(-\infty,-1\)\cup[2,\infty)). The expression inside the square root must satisfy \(\frac{x-2}{x+1}\ge 0\) and \(x\ne -1\). A sign table gives (\(-\infty,-1\)\cup[2,\infty)).
Exam Tip
वर्गमूल के अंदर \(\frac{x-2}{x+1}\ge 0\) और \(x\ne -1\) चाहिए। संकेत तालिका से (\(-\infty,-1\)\cup[2,\infty)) मिलता है।
Login to save your score, XP, coins and progress.