तंत्र \(3x+y\leq 6\), \(x-y\geq 0\), \(y\geq 0\) के हल क्षेत्र के शीर्ष कौन-से हैं?
What are the vertices of the solution region of \(3x+y\leq 6\), \(x-y\geq 0\), \(y\geq 0\)?
Explanation opens after your attempt
C. ((0,0)), ((2,0)), (\(\frac{3}{2},\frac{3}{2}\))
Concept
The condition \(x-y\geq 0\) gives \(y\leq x\), and its intersection with (3x+y=6) is (\(\frac{3}{2},\frac{3}{2}\)). Exam tip: Reading the region is easier after rewriting inequalities.
Why this answer is correct
The correct answer is C. ((0,0)), ((2,0)), (\(\frac{3}{2},\frac{3}{2}\)). The condition \(x-y\geq 0\) gives \(y\leq x\), and its intersection with (3x+y=6) is (\(\frac{3}{2},\frac{3}{2}\)). Exam tip: Reading the region is easier after rewriting inequalities.
Exam Tip
\(x-y\geq 0\) से \(y\leq x\) और (3x+y=6) से प्रतिच्छेद (\(\frac{3}{2},\frac{3}{2}\)) मिलता है। परीक्षा सुझाव: बदले हुए रूप में क्षेत्र पढ़ना आसान होता है।
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