यदि \(x\in \mathbb{Z}\) और \( \frac{x+2}{3}>1 \) तथा (x<9), तो कितने पूर्णांक हल हैं?
If \(x\in \mathbb{Z}\) and \( \frac{x+2}{3}>1 \) and (x<9), how many integer solutions are there?
Explanation opens after your attempt
Correct Answer
A. (5)
Concept
The first condition gives (x>1) and the second gives (x<9), so (x=2,3,4,5,6,7,8), which are (7) integers. Always list integer endpoints carefully.
Why this answer is correct
The correct answer is A. (5). The first condition gives (x>1) and the second gives (x<9), so (x=2,3,4,5,6,7,8), which are (7) integers. Always list integer endpoints carefully.
Exam Tip
पहली शर्त से (x>1) और दूसरी से (x<9) है इसलिए (x=2,3,4,5,6,7,8) कुल (7) नहीं बल्कि विकल्प जांचने पर (7) होना चाहिए।
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