यदि \(U={x:x\in \mathbb{Z},-5\le x\le 5}\) और \(A={x:x^2\le 9}\), तो (A') क्या होगा?

If \(U={x:x\in \mathbb{Z},-5\le x\le 5}\) and \(A={x:x^2\le 9}\), what is (A')?

Explanation opens after your attempt
Correct Answer

A. \({-5,-4,4,5})

Step 1

Concept

Here \(A=\{-3,-2,-1,0,1,2,3\}\), so the remaining elements of (U) form (A'). In exams, always find complement inside (U).

Step 2

Why this answer is correct

The correct answer is A. \({-5,-4,4,5}). Here \(A=\{-3,-2,-1,0,1,2,3\}\), so the remaining elements of (U) form (A'). In exams, always find complement inside (U).

Step 3

Exam Tip

\(A=\{-3,-2,-1,0,1,2,3\}\) है, इसलिए (U) के बचे अवयव (A') होंगे। परीक्षा में पूरक हमेशा (U) के अंदर ही निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={x:x\in \mathbb{Z},-5\le x\le 5}\) और \(A={x:x^2\le 9}\), तो (A') क्या होगा? / If \(U={x:x\in \mathbb{Z},-5\le x\le 5}\) and \(A={x:x^2\le 9}\), what is (A')?

Correct Answer: A. \({-5,-4,4,5}). Explanation: \(A=\{-3,-2,-1,0,1,2,3\}\) है, इसलिए (U) के बचे अवयव (A') होंगे। परीक्षा में पूरक हमेशा (U) के अंदर ही निकालें। / Here \(A=\{-3,-2,-1,0,1,2,3\}\), so the remaining elements of (U) form (A'). In exams, always find complement inside (U).

Which concept should I revise for this Mathematics MCQ?

Here \(A=\{-3,-2,-1,0,1,2,3\}\), so the remaining elements of (U) form (A'). In exams, always find complement inside (U).

What exam hint can help solve this Mathematics question?

\(A=\{-3,-2,-1,0,1,2,3\}\) है, इसलिए (U) के बचे अवयव (A') होंगे। परीक्षा में पूरक हमेशा (U) के अंदर ही निकालें।