यदि \(U={x:x\in \mathbb{N}, x\leq 15}\) और \(A={x:x\) (5) का गुणज है(}), तो (n(A')) कितना होगा?

If \(U={x:x\in \mathbb{N}, x\leq 15}\) and \(A={x:x\) is a multiple of (5)(}), what is (n(A'))?

Explanation opens after your attempt
Correct Answer

D. (12)

Step 1

Concept

\(A=\{5,10,15\}\), so (n(A)=3). Since (U) has (15) elements, (n(A')=15-3=12).

Step 2

Why this answer is correct

The correct answer is D. (12). \(A=\{5,10,15\}\), so (n(A)=3). Since (U) has (15) elements, (n(A')=15-3=12).

Step 3

Exam Tip

\(A=\{5,10,15\}\) है, इसलिए (n(A)=3)। (U) में (15) तत्व हैं, अतः (n(A')=15-3=12)।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U={x:x\in \mathbb{N}, x\leq 15}\) और \(A={x:x\) (5) का गुणज है(}), तो (n(A')) कितना होगा? / If \(U={x:x\in \mathbb{N}, x\leq 15}\) and \(A={x:x\) is a multiple of (5)(}), what is (n(A'))?

Correct Answer: D. (12). Explanation: \(A=\{5,10,15\}\) है, इसलिए (n(A)=3)। (U) में (15) तत्व हैं, अतः (n(A')=15-3=12)। / \(A=\{5,10,15\}\), so (n(A)=3). Since (U) has (15) elements, (n(A')=15-3=12).

Which concept should I revise for this Mathematics MCQ?

\(A=\{5,10,15\}\), so (n(A)=3). Since (U) has (15) elements, (n(A')=15-3=12).

What exam hint can help solve this Mathematics question?

\(A=\{5,10,15\}\) है, इसलिए (n(A)=3)। (U) में (15) तत्व हैं, अतः (n(A')=15-3=12)।