यदि \(U=\mathbb{R}\) और \(A={x:x \in \mathbb{R},x^2-6x+8>0}\), तो (A') क्या है?
If \(U=\mathbb{R}\) and \(A={x:x \in \mathbb{R},x^2-6x+8>0}\), what is (A')?
Explanation opens after your attempt
Correct Answer
A. ([2,4])
Concept
The solution of \(x^2-6x+8>0\) is (x<2) or (x>4). Thus the complement is \(2\le x\le 4\).
Why this answer is correct
The correct answer is A. ([2,4]). The solution of \(x^2-6x+8>0\) is (x<2) or (x>4). Thus the complement is \(2\le x\le 4\).
Exam Tip
\(x^2-6x+8>0\) का हल (x<2) या (x>4) है। इसलिए पूरक में \(2\le x\le 4\) आएगा।
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