यदि \(U=\{a,b,c,d,e,f,g,h\}\), (A'={b,d,f,h}) और \(B=\{a,b,c,d\}\), तो \(A\cap B'\) क्या है?

If \(U=\{a,b,c,d,e,f,g,h\}\), (A'={b,d,f,h}) and \(B=\{a,b,c,d\}\), what is \(A\cap B'\)?

Explanation opens after your attempt
Correct Answer

A. \({e,g})

Step 1

Concept

(A=U-A'={a,c,e,g}) and (B'={e,f,g,h}), so \(A\cap B'={e,g}\). First recover the original set from its complement.

Step 2

Why this answer is correct

The correct answer is A. \({e,g}). (A=U-A'={a,c,e,g}) and (B'={e,f,g,h}), so \(A\cap B'={e,g}\). First recover the original set from its complement.

Step 3

Exam Tip

(A=U-A'={a,c,e,g}) और (B'={e,f,g,h}), इसलिए \(A\cap B'={e,g}\)। दिए गए पूरक से पहले मूल समुच्चय निकालें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(U=\{a,b,c,d,e,f,g,h\}\), (A'={b,d,f,h}) और \(B=\{a,b,c,d\}\), तो \(A\cap B'\) क्या है? / If \(U=\{a,b,c,d,e,f,g,h\}\), (A'={b,d,f,h}) and \(B=\{a,b,c,d\}\), what is \(A\cap B'\)?

Correct Answer: A. \({e,g}). Explanation: (A=U-A'={a,c,e,g}) और (B'={e,f,g,h}), इसलिए \(A\cap B'={e,g}\)। दिए गए पूरक से पहले मूल समुच्चय निकालें। / (A=U-A'={a,c,e,g}) and (B'={e,f,g,h}), so \(A\cap B'={e,g}\). First recover the original set from its complement.

Which concept should I revise for this Mathematics MCQ?

(A=U-A'={a,c,e,g}) and (B'={e,f,g,h}), so \(A\cap B'={e,g}\). First recover the original set from its complement.

What exam hint can help solve this Mathematics question?

(A=U-A'={a,c,e,g}) और (B'={e,f,g,h}), इसलिए \(A\cap B'={e,g}\)। दिए गए पूरक से पहले मूल समुच्चय निकालें।