यदि \(U={1,2,\ldots,72}\), (A) (4) के गुणजों का समुच्चय है और (B) (9) के गुणजों का समुच्चय है, तो (|\(A\cup B\)'|) कितना है?
If \(U={1,2,\ldots,72}\), (A) is the set of multiples of (4) and (B) is the set of multiples of (9), then what is (|\(A\cup B\)'|)?
Explanation opens after your attempt
A. (48)
Concept
(A) has (18) elements, (B) has (8), and \(A\cap B\) has (2) multiples of (36), so \(|A\cup B|=24\). Hence (|\(A\cup B\)'|=72-24=48).
Why this answer is correct
The correct answer is A. (48). (A) has (18) elements, (B) has (8), and \(A\cap B\) has (2) multiples of (36), so \(|A\cup B|=24\). Hence (|\(A\cup B\)'|=72-24=48).
Exam Tip
(A) में (18), (B) में (8) और \(A\cap B\) में (36) के (2) गुणज हैं, इसलिए \(|A\cup B|=18+8-2=24\)। अतः (|\(A\cup B\)'|=72-24=48)।
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