\(यदि (U={1,2,\ldots,40}), (A={x:x\) अभाज्य है\(}) और (B={x:x\) विषम है\(}), तो (|A'\cap B|) कितना है\)?
\(If (U={1,2,\ldots,40}), (A={x:x\) is prime\(}) and (B={x:x\) is odd\(}), what is (|A'\cap B|)\)?
Explanation opens after your attempt
Correct Answer
D. (10)
Concept
There are (20) odd numbers from (1) to (40), and (10) of them are prime. So odd but not prime numbers are (20-10=10).
Why this answer is correct
The correct answer is D. (10). There are (20) odd numbers from (1) to (40), and (10) of them are prime. So odd but not prime numbers are (20-10=10).
Exam Tip
(1) से (40) तक (20) विषम संख्याएँ हैं और उनमें (10) अभाज्य हैं। इसलिए विषम पर अभाज्य नहीं संख्याएँ (20-10=10) हैं।
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