यदि \(U={1,2,\ldots,20}\) और (A) सभी अभाज्य संख्याओं का समुच्चय है, तो (n(\mathcal{P}(A'))) कितना है?

If \(U={1,2,\ldots,20}\) and (A) is the set of all prime numbers, what is (n(\mathcal{P}(A')))?

Explanation opens after your attempt
Correct Answer

A. (4096)

Step 1

Concept

There are (8) primes from (1) to (20), so (A') has (12) elements. Hence (n(\mathcal{P}(A'))=2^{12}=4096).

Step 2

Why this answer is correct

The correct answer is A. (4096). There are (8) primes from (1) to (20), so (A') has (12) elements. Hence (n(\mathcal{P}(A'))=2^{12}=4096).

Step 3

Exam Tip

(1) से (20) तक (8) अभाज्य संख्याएं हैं, इसलिए (A') में (12) तत्व हैं। अतः (n(\mathcal{P}(A'))=2^{12}=4096)।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि \(U={1,2,\ldots,20}\) और (A) सभी अभाज्य संख्याओं का समुच्चय है, तो (n(\mathcal{P}(A'))) कितना है? / If \(U={1,2,\ldots,20}\) and (A) is the set of all prime numbers, what is (n(\mathcal{P}(A')))?

Correct Answer: A. (4096). Explanation: (1) से (20) तक (8) अभाज्य संख्याएं हैं, इसलिए (A') में (12) तत्व हैं। अतः (n(\mathcal{P}(A'))=2^{12}=4096)। / There are (8) primes from (1) to (20), so (A') has (12) elements. Hence (n(\mathcal{P}(A'))=2^{12}=4096).

Which concept should I revise for this Mathematics MCQ?

There are (8) primes from (1) to (20), so (A') has (12) elements. Hence (n(\mathcal{P}(A'))=2^{12}=4096).

What exam hint can help solve this Mathematics question?

(1) से (20) तक (8) अभाज्य संख्याएं हैं, इसलिए (A') में (12) तत्व हैं। अतः (n(\mathcal{P}(A'))=2^{12}=4096)।