\(यदि (U={1,2,\ldots,10}) और (A={x:x \in U\) तथा \(x^2-11x+30=0}), तो (A' \cap {5,6,7,8}) क्या है\)?
\(If (U={1,2,\ldots,10}) and (A={x:x \in U\) and \(x^2-11x+30=0}), what is (A' \cap {5,6,7,8})\)?
Explanation opens after your attempt
Correct Answer
A. ({7,8})
Concept
The equation gives \(A=\{5,6\}\), so (5) and (6) are not in (A'). From the given set, ({7,8}) remains.
Why this answer is correct
The correct answer is A. ({7,8}). The equation gives \(A=\{5,6\}\), so (5) and (6) are not in (A'). From the given set, ({7,8}) remains.
Exam Tip
समीकरण से \(A=\{5,6\}\) मिलता है, इसलिए (A') में (5) और (6) नहीं होंगे। दिए गए समुच्चय से ({7,8}) बचता है।
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