यदि \(U=\{1,2,3,4,5\}\) और \(A=\{1,2\}\), तो \(\mathcal{P}(A')\subseteq\mathcal{P}(U)\) क्यों सत्य है?
If \(U=\{1,2,3,4,5\}\) and \(A=\{1,2\}\), why is \(\mathcal{P}(A')\subseteq\mathcal{P}(U)\) true?
Explanation opens after your attempt
Correct Answer
A. क्योंकि \(A'\subseteq U\)Because \(A'\subseteq U\)
Concept
Every complement (A') contains elements only from (U). Thus \(A'\subseteq U\) gives \(\mathcal{P}(A')\subseteq\mathcal{P}(U)\).
Why this answer is correct
The correct answer is A. क्योंकि \(A'\subseteq U\) / Because \(A'\subseteq U\). Every complement (A') contains elements only from (U). Thus \(A'\subseteq U\) gives \(\mathcal{P}(A')\subseteq\mathcal{P}(U)\).
Exam Tip
किसी भी पूरक (A') के सभी तत्व (U) के अंदर ही होते हैं। इसलिए \(A'\subseteq U\) से \(\mathcal{P}(A')\subseteq\mathcal{P}(U)\) मिलता है।
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