यदि (f(x)=\sqrt{x-a}) का प्रांत \([7,\infty\)) है, तो (a) का मान क्या है?
If the domain of (f(x)=\sqrt{x-a}) is \([7,\infty\)), what is the value of (a)?
Explanation opens after your attempt
A. (7)
Concept
For \(\sqrt{x-a}\), \(x-a\ge 0\), so \(x\ge a\). Comparing with the given domain gives (a=7).
Why this answer is correct
The correct answer is A. (7). For \(\sqrt{x-a}\), \(x-a\ge 0\), so \(x\ge a\). Comparing with the given domain gives (a=7).
Exam Tip
\(\sqrt{x-a}\) के लिए \(x-a\ge 0\), यानी \(x\ge a\)। दिए गए प्रांत से (a=7) है।
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