यदि (f(x)=\sqrt{x-a}) का प्रांत \([7,\infty\)) है, तो (a) का मान क्या है?

If the domain of (f(x)=\sqrt{x-a}) is \([7,\infty\)), what is the value of (a)?

Explanation opens after your attempt
Correct Answer

A. (7)

Step 1

Concept

For \(\sqrt{x-a}\), \(x-a\ge 0\), so \(x\ge a\). Comparing with the given domain gives (a=7).

Step 2

Why this answer is correct

The correct answer is A. (7). For \(\sqrt{x-a}\), \(x-a\ge 0\), so \(x\ge a\). Comparing with the given domain gives (a=7).

Step 3

Exam Tip

\(\sqrt{x-a}\) के लिए \(x-a\ge 0\), यानी \(x\ge a\)। दिए गए प्रांत से (a=7) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x-a}) का प्रांत \([7,\infty\)) है, तो (a) का मान क्या है? / If the domain of (f(x)=\sqrt{x-a}) is \([7,\infty\)), what is the value of (a)?

Correct Answer: A. (7). Explanation: \(\sqrt{x-a}\) के लिए \(x-a\ge 0\), यानी \(x\ge a\)। दिए गए प्रांत से (a=7) है। / For \(\sqrt{x-a}\), \(x-a\ge 0\), so \(x\ge a\). Comparing with the given domain gives (a=7).

Which concept should I revise for this Mathematics MCQ?

For \(\sqrt{x-a}\), \(x-a\ge 0\), so \(x\ge a\). Comparing with the given domain gives (a=7).

What exam hint can help solve this Mathematics question?

\(\sqrt{x-a}\) के लिए \(x-a\ge 0\), यानी \(x\ge a\)। दिए गए प्रांत से (a=7) है।