यदि (n(U)=50), (n(A)=20), (n(B)=16), और (n\(A\cap B\)=6), तो न (A) न (B) में कितने अवयव हैं?
If (n(U)=50), (n(A)=20), (n(B)=16), and (n\(A\cap B\)=6), how many elements are in neither (A) nor (B)?
Explanation opens after your attempt
B. (20)
Concept
First (n\(A\cup B\)=20+16-6=30). Then neither (A) nor (B) has (50-30=20) elements.
Why this answer is correct
The correct answer is B. (20). First (n\(A\cup B\)=20+16-6=30). Then neither (A) nor (B) has (50-30=20) elements.
Exam Tip
पहले (n\(A\cup B\)=20+16-6=30)। फिर न (A) न (B) में (50-30=20) होंगे।
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