यदि (n(U)=50), (n(A)=20), (n(B)=16), और (n\(A\cap B\)=6), तो न (A) न (B) में कितने अवयव हैं?

If (n(U)=50), (n(A)=20), (n(B)=16), and (n\(A\cap B\)=6), how many elements are in neither (A) nor (B)?

Explanation opens after your attempt
Correct Answer

B. (20)

Step 1

Concept

First (n\(A\cup B\)=20+16-6=30). Then neither (A) nor (B) has (50-30=20) elements.

Step 2

Why this answer is correct

The correct answer is B. (20). First (n\(A\cup B\)=20+16-6=30). Then neither (A) nor (B) has (50-30=20) elements.

Step 3

Exam Tip

पहले (n\(A\cup B\)=20+16-6=30)। फिर न (A) न (B) में (50-30=20) होंगे।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(U)=50), (n(A)=20), (n(B)=16), और (n\(A\cap B\)=6), तो न (A) न (B) में कितने अवयव हैं? / If (n(U)=50), (n(A)=20), (n(B)=16), and (n\(A\cap B\)=6), how many elements are in neither (A) nor (B)?

Correct Answer: B. (20). Explanation: पहले (n\(A\cup B\)=20+16-6=30)। फिर न (A) न (B) में (50-30=20) होंगे। / First (n\(A\cup B\)=20+16-6=30). Then neither (A) nor (B) has (50-30=20) elements.

Which concept should I revise for this Mathematics MCQ?

First (n\(A\cup B\)=20+16-6=30). Then neither (A) nor (B) has (50-30=20) elements.

What exam hint can help solve this Mathematics question?

पहले (n\(A\cup B\)=20+16-6=30)। फिर न (A) न (B) में (50-30=20) होंगे।