यदि (n(U)=140), (n(A')=58), (n(B')=71) और (n\(A\cap B\)=34) है, तो (n\(A\cup B\)) कितना है?
If (n(U)=140), (n(A')=58), (n(B')=71) and (n\(A\cap B\)=34), then what is (n\(A\cup B\))?
Explanation opens after your attempt
Correct Answer
A. (117)
Concept
(n(A)=140-58=82) and (n(B)=140-71=69), so the union is (82+69-34=117). Getting original sizes from complements is the first step.
Why this answer is correct
The correct answer is A. (117). (n(A)=140-58=82) and (n(B)=140-71=69), so the union is (82+69-34=117). Getting original sizes from complements is the first step.
Exam Tip
(n(A)=140-58=82) और (n(B)=140-71=69), इसलिए संघ (82+69-34=117) है। पूरक से मूल संख्या निकालना पहला कदम है।
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