यदि (^{n}P_r=\frac{n!}{(n-r)!}) है तो \(^{n}P_{r-1}\) किसके बराबर होगा?

If (^{n}P_r=\frac{n!}{(n-r)!}) then what is \(^{n}P_{r-1}\)?

Explanation opens after your attempt
Correct Answer

A. (\frac{n!}{(n-r+1)!})

Step 1

Concept

Putting (r-1) makes the denominator ((n-r+1)!). In exams watch signs carefully while substituting.

Step 2

Why this answer is correct

The correct answer is A. (\frac{n!}{(n-r+1)!}). Putting (r-1) makes the denominator ((n-r+1)!). In exams watch signs carefully while substituting.

Step 3

Exam Tip

(r-1) रखने पर हर ((n-r+1)!) बनता है। परीक्षा में substitution करते समय signs ध्यान से देखें।

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Mathematics Answer, Explanation and Revision Hints

यदि (^{n}P_r=\frac{n!}{(n-r)!}) है तो \(^{n}P_{r-1}\) किसके बराबर होगा? / If (^{n}P_r=\frac{n!}{(n-r)!}) then what is \(^{n}P_{r-1}\)?

Correct Answer: A. (\frac{n!}{(n-r+1)!}). Explanation: (r-1) रखने पर हर ((n-r+1)!) बनता है। परीक्षा में substitution करते समय signs ध्यान से देखें। / Putting (r-1) makes the denominator ((n-r+1)!). In exams watch signs carefully while substituting.

Which concept should I revise for this Mathematics MCQ?

Putting (r-1) makes the denominator ((n-r+1)!). In exams watch signs carefully while substituting.

What exam hint can help solve this Mathematics question?

(r-1) रखने पर हर ((n-r+1)!) बनता है। परीक्षा में substitution करते समय signs ध्यान से देखें।