यदि (n\(A\cap B\)=0), (n(A)=39) और (n(B)=48) है, तो (n\(A\triangle B\)) कितना है?
If (n\(A\cap B\)=0), (n(A)=39) and (n(B)=48), then what is (n\(A\triangle B\))?
Explanation opens after your attempt
Correct Answer
A. (87)
Concept
The intersection is zero, so the symmetric difference is the whole union (39+48=87). For disjoint sets, no common part needs removal.
Why this answer is correct
The correct answer is A. (87). The intersection is zero, so the symmetric difference is the whole union (39+48=87). For disjoint sets, no common part needs removal.
Exam Tip
प्रतिच्छेद शून्य है, इसलिए सममित अंतर पूरा संघ (39+48=87) है। असंबद्ध समुच्चयों में कोई साझा भाग हटाना नहीं पड़ता।
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