यदि (n\(A\cap B\)=0) और (n(A)=28), (n(B)=34) है, तो (n\(A\triangle B\)) कितना है?
If (n\(A\cap B\)=0) and (n(A)=28), (n(B)=34), then what is (n\(A\triangle B\))?
Explanation opens after your attempt
Correct Answer
A. (62)
Concept
For disjoint sets, the symmetric difference is the whole union, so (28+34=62). When the common part is zero, nothing needs to be removed.
Why this answer is correct
The correct answer is A. (62). For disjoint sets, the symmetric difference is the whole union, so (28+34=62). When the common part is zero, nothing needs to be removed.
Exam Tip
असंबद्ध समुच्चयों में सममित अंतर पूरा संघ होता है, इसलिए (28+34=62) है। साझा भाग शून्य होने पर कुछ हटाना नहीं पड़ता।
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