यदि (n(A)=8), (n(B)=6) और (n\(A\cup B\)=10) हैं, तो (n\(A\cap B\)) क्या है?
If (n(A)=8), (n(B)=6), and (n\(A\cup B\)=10), what is (n\(A\cap B\))?
Explanation opens after your attempt
A. (4)
Concept
(n\(A\cap B\)=n(A)+n(B)-n\(A\cup B\)). Hence (8+6-10=4).
Why this answer is correct
The correct answer is A. (4). (n\(A\cap B\)=n(A)+n(B)-n\(A\cup B\)). Hence (8+6-10=4).
Exam Tip
(n\(A\cap B\)=n(A)+n(B)-n\(A\cup B\)) होता है। अतः (8+6-10=4) है।
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