यदि (n(A)=69), (n(B)=74), (n(A-B)=28) है, तो (n\(A\cup B\)) कितना है?
If (n(A)=69), (n(B)=74), (n(A-B)=28), then what is (n\(A\cup B\))?
Explanation opens after your attempt
A. (102)
Concept
(n\(A\cap B\)=69-28=41), so (n\(A\cup B\)=69+74-41=102). Find the common part first.
Why this answer is correct
The correct answer is A. (102). (n\(A\cap B\)=69-28=41), so (n\(A\cup B\)=69+74-41=102). Find the common part first.
Exam Tip
(n\(A\cap B\)=69-28=41), इसलिए (n\(A\cup B\)=69+74-41=102) है। पहले साझा भाग खोजें।
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