यदि (n(A)=64), (n(B)=59) और (n\(A\cup B\)=91) है, तो (n\(A\triangle B\)) कितना है?
If (n(A)=64), (n(B)=59) and (n\(A\cup B\)=91), then what is (n\(A\triangle B\))?
Explanation opens after your attempt
Correct Answer
A. (59)
Concept
First (n\(A\cap B\)=64+59-91=32), then (n\(A\triangle B\)=91-32=59). The symmetric difference does not include the common part.
Why this answer is correct
The correct answer is A. (59). First (n\(A\cap B\)=64+59-91=32), then (n\(A\triangle B\)=91-32=59). The symmetric difference does not include the common part.
Exam Tip
पहले (n\(A\cap B\)=64+59-91=32), फिर (n\(A\triangle B\)=91-32=59) है। सममित अंतर में साझा भाग नहीं आता।
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