यदि (n(A)=5x+4), (n(B)=4x+7), (n\(A\cap B\)=2x+3) और (n\(A\cup B\)=78) है, तो (x) का मान क्या है?
If (n(A)=5x+4), (n(B)=4x+7), (n\(A\cap B\)=2x+3) and (n\(A\cup B\)=78), then what is the value of (x)?
Explanation opens after your attempt
A. (10)
Concept
(78=(5x+4)+(4x+7)-(2x+3)=7x+8), so (x=10). In algebraic questions, apply the union formula directly.
Why this answer is correct
The correct answer is A. (10). (78=(5x+4)+(4x+7)-(2x+3)=7x+8), so (x=10). In algebraic questions, apply the union formula directly.
Exam Tip
(78=(5x+4)+(4x+7)-(2x+3)=7x+8), इसलिए (x=10) है। बीजगणितीय प्रश्न में संघ का सूत्र सीधे लगाएँ।
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