यदि (n(A)=48), (n(B)=52), (n(A-B)=17) और (n(B-A)=21) है, तो (n\(A\cap B\)) कितना होगा?
If (n(A)=48), (n(B)=52), (n(A-B)=17), and (n(B-A)=21), what is (n\(A\cap B\))?
Explanation opens after your attempt
A. (31)
Concept
(n\(A\cap B\)=n(A)-n(A-B)=48-17=31). From (B), (52-21=31) should also match.
Why this answer is correct
The correct answer is A. (31). (n\(A\cap B\)=n(A)-n(A-B)=48-17=31). From (B), (52-21=31) should also match.
Exam Tip
(n\(A\cap B\)=n(A)-n(A-B)=48-17=31)। (B) से भी (52-21=31) मिलना चाहिए।
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