यदि (n(A)=18) और (n\(A\cap B\)=6), तो केवल (A) में कितने अवयव होंगे?

If (n(A)=18) and (n\(A\cap B\)=6), how many elements are only in (A)?

Explanation opens after your attempt
Correct Answer

B. (12)

Step 1

Concept

The number only in (A) is (n(A)-n\(A\cap B\)=18-6=12). Subtract the common part from total (A).

Step 2

Why this answer is correct

The correct answer is B. (12). The number only in (A) is (n(A)-n\(A\cap B\)=18-6=12). Subtract the common part from total (A).

Step 3

Exam Tip

केवल (A) की संख्या (n(A)-n\(A\cap B\)=18-6=12) है। कुल (A) से साझा भाग घटाएं।

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Mathematics Answer, Explanation and Revision Hints

यदि (n(A)=18) और (n\(A\cap B\)=6), तो केवल (A) में कितने अवयव होंगे? / If (n(A)=18) and (n\(A\cap B\)=6), how many elements are only in (A)?

Correct Answer: B. (12). Explanation: केवल (A) की संख्या (n(A)-n\(A\cap B\)=18-6=12) है। कुल (A) से साझा भाग घटाएं। / The number only in (A) is (n(A)-n\(A\cap B\)=18-6=12). Subtract the common part from total (A).

Which concept should I revise for this Mathematics MCQ?

The number only in (A) is (n(A)-n\(A\cap B\)=18-6=12). Subtract the common part from total (A).

What exam hint can help solve this Mathematics question?

केवल (A) की संख्या (n(A)-n\(A\cap B\)=18-6=12) है। कुल (A) से साझा भाग घटाएं।