यदि (f(x)=x+\frac{2}{x}) और (g(x)=x-\frac{2}{x}) हैं, तो ((fg)(x)) किसके बराबर है?

If (f(x)=x+\frac{2}{x}) and (g(x)=x-\frac{2}{x}), what is ((fg)(x)) equal to?

Explanation opens after your attempt
Correct Answer

A. \(x^2-\frac{4}{x^2}\), \(x\ne 0\)

Step 1

Concept

((fg)(x)=\left\(x+\frac{2}{x}\right\)\left\(x-\frac{2}{x}\right\)=x-2-\frac{4}{x-2}). Apply ((a+b)(a-b)=a-2-b-2).

Step 2

Why this answer is correct

The correct answer is A. \(x^2-\frac{4}{x^2}\), \(x\ne 0\). ((fg)(x)=\left\(x+\frac{2}{x}\right\)\left\(x-\frac{2}{x}\right\)=x-2-\frac{4}{x-2}). Apply ((a+b)(a-b)=a-2-b-2).

Step 3

Exam Tip

((fg)(x)=\left\(x+\frac{2}{x}\right\)\left\(x-\frac{2}{x}\right\)=x-2-\frac{4}{x-2})। पहचान ((a+b)(a-b)=a-2-b-2) लगाएं।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x+\frac{2}{x}) और (g(x)=x-\frac{2}{x}) हैं, तो ((fg)(x)) किसके बराबर है? / If (f(x)=x+\frac{2}{x}) and (g(x)=x-\frac{2}{x}), what is ((fg)(x)) equal to?

Correct Answer: A. \(x^2-\frac{4}{x^2}\), \(x\ne 0\). Explanation: ((fg)(x)=\left\(x+\frac{2}{x}\right\)\left\(x-\frac{2}{x}\right\)=x-2-\frac{4}{x-2})। पहचान ((a+b)(a-b)=a-2-b-2) लगाएं। / ((fg)(x)=\left\(x+\frac{2}{x}\right\)\left\(x-\frac{2}{x}\right\)=x-2-\frac{4}{x-2}). Apply ((a+b)(a-b)=a-2-b-2).

Which concept should I revise for this Mathematics MCQ?

((fg)(x)=\left\(x+\frac{2}{x}\right\)\left\(x-\frac{2}{x}\right\)=x-2-\frac{4}{x-2}). Apply ((a+b)(a-b)=a-2-b-2).

What exam hint can help solve this Mathematics question?

((fg)(x)=\left\(x+\frac{2}{x}\right\)\left\(x-\frac{2}{x}\right\)=x-2-\frac{4}{x-2})। पहचान ((a+b)(a-b)=a-2-b-2) लगाएं।