यदि (f(x)=x-2) और (g(x)=|x|) हों, तो ((f-g)(x)) का मान (0) कब होगा?
If (f(x)=x-2) and (g(x)=|x|), when is ((f-g)(x)) equal to (0)?
Explanation opens after your attempt
A. \(x\in{-1,0,1}\)
Concept
In \(x^2=|x|\), put \(t=|x|\ge 0\), so \(t^2=t\). Thus (t=0) or (t=1), giving (x=-1,0,1).
Why this answer is correct
The correct answer is A. \(x\in{-1,0,1}\). In \(x^2=|x|\), put \(t=|x|\ge 0\), so \(t^2=t\). Thus (t=0) or (t=1), giving (x=-1,0,1).
Exam Tip
\(x^2=|x|\) में \(t=|x|\ge 0\) रखने पर \(t^2=t\), इसलिए (t=0) या (t=1)। अतः (x=-1,0,1) हैं।
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