यदि (f(x)=x-2) और (g(x)=4) हैं, तो \(\frac{f}{g}\) का परास क्या है?

If (f(x)=x-2) and (g(x)=4), what is the range of \(\frac{f}{g}\)?

Explanation opens after your attempt
Correct Answer

A. \([0,\infty\))

Step 1

Concept

\(\frac{f}{g}=\frac{x^2}{4}\) and \(x^2\ge 0\), so the range is \([0,\infty\)). Division by a positive constant does not change sign.

Step 2

Why this answer is correct

The correct answer is A. \([0,\infty\)). \(\frac{f}{g}=\frac{x^2}{4}\) and \(x^2\ge 0\), so the range is \([0,\infty\)). Division by a positive constant does not change sign.

Step 3

Exam Tip

\(\frac{f}{g}=\frac{x^2}{4}\) और \(x^2\ge 0\), इसलिए परास \([0,\infty\)) है। धन स्थिर से भाग देने पर चिन्ह नहीं बदलता।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2) और (g(x)=4) हैं, तो \(\frac{f}{g}\) का परास क्या है? / If (f(x)=x-2) and (g(x)=4), what is the range of \(\frac{f}{g}\)?

Correct Answer: A. \([0,\infty\)). Explanation: \(\frac{f}{g}=\frac{x^2}{4}\) और \(x^2\ge 0\), इसलिए परास \([0,\infty\)) है। धन स्थिर से भाग देने पर चिन्ह नहीं बदलता। / \(\frac{f}{g}=\frac{x^2}{4}\) and \(x^2\ge 0\), so the range is \([0,\infty\)). Division by a positive constant does not change sign.

Which concept should I revise for this Mathematics MCQ?

\(\frac{f}{g}=\frac{x^2}{4}\) and \(x^2\ge 0\), so the range is \([0,\infty\)). Division by a positive constant does not change sign.

What exam hint can help solve this Mathematics question?

\(\frac{f}{g}=\frac{x^2}{4}\) और \(x^2\ge 0\), इसलिए परास \([0,\infty\)) है। धन स्थिर से भाग देने पर चिन्ह नहीं बदलता।