यदि (f(x)=x-2-4) और (g(x)=x-2) हैं तो (\left\(\frac{f}{g}\right\)(x)) का सरल रूप और प्रतिबंध क्या है?
If (f(x)=x-2-4) and (g(x)=x-2) then what is the simplified form and restriction of (\left\(\frac{f}{g}\right\)(x))?
Explanation opens after your attempt
A. (x+2), \(x\ne 2\)
Concept
(\left\(\frac{f}{g}\right\)(x)=\frac{x-2-4}{x-2}=x+2) but \(x\ne 2\). Even after simplifying do not forget the original denominator restriction.
Why this answer is correct
The correct answer is A. (x+2), \(x\ne 2\). (\left\(\frac{f}{g}\right\)(x)=\frac{x-2-4}{x-2}=x+2) but \(x\ne 2\). Even after simplifying do not forget the original denominator restriction.
Exam Tip
(\left\(\frac{f}{g}\right\)(x)=\frac{x-2-4}{x-2}=x+2) पर \(x\ne 2\)। सरल करने के बाद भी मूल हर का प्रतिबंध न भूलें।
Login to save your score, XP, coins and progress.
