यदि (f(x)=x-2-4) और (g(x)=x-2) हैं तो (\left\(\frac{f}{g}\right\)(x)) का सरल रूप और प्रतिबंध क्या है?

If (f(x)=x-2-4) and (g(x)=x-2) then what is the simplified form and restriction of (\left\(\frac{f}{g}\right\)(x))?

Explanation opens after your attempt
Correct Answer

A. (x+2), \(x\ne 2\)

Step 1

Concept

(\left\(\frac{f}{g}\right\)(x)=\frac{x-2-4}{x-2}=x+2) but \(x\ne 2\). Even after simplifying do not forget the original denominator restriction.

Step 2

Why this answer is correct

The correct answer is A. (x+2), \(x\ne 2\). (\left\(\frac{f}{g}\right\)(x)=\frac{x-2-4}{x-2}=x+2) but \(x\ne 2\). Even after simplifying do not forget the original denominator restriction.

Step 3

Exam Tip

(\left\(\frac{f}{g}\right\)(x)=\frac{x-2-4}{x-2}=x+2) पर \(x\ne 2\)। सरल करने के बाद भी मूल हर का प्रतिबंध न भूलें।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2-4) और (g(x)=x-2) हैं तो (\left\(\frac{f}{g}\right\)(x)) का सरल रूप और प्रतिबंध क्या है? / If (f(x)=x-2-4) and (g(x)=x-2) then what is the simplified form and restriction of (\left\(\frac{f}{g}\right\)(x))?

Correct Answer: A. (x+2), \(x\ne 2\). Explanation: (\left\(\frac{f}{g}\right\)(x)=\frac{x-2-4}{x-2}=x+2) पर \(x\ne 2\)। सरल करने के बाद भी मूल हर का प्रतिबंध न भूलें। / (\left\(\frac{f}{g}\right\)(x)=\frac{x-2-4}{x-2}=x+2) but \(x\ne 2\). Even after simplifying do not forget the original denominator restriction.

Which concept should I revise for this Mathematics MCQ?

(\left\(\frac{f}{g}\right\)(x)=\frac{x-2-4}{x-2}=x+2) but \(x\ne 2\). Even after simplifying do not forget the original denominator restriction.

What exam hint can help solve this Mathematics question?

(\left\(\frac{f}{g}\right\)(x)=\frac{x-2-4}{x-2}=x+2) पर \(x\ne 2\)। सरल करने के बाद भी मूल हर का प्रतिबंध न भूलें।