यदि (f(x)=x-2+2x+2) और (g(x)=x+1) हैं, तो ((f-g)(x)) का न्यूनतम मान क्या होगा?

If (f(x)=x-2+2x+2) and (g(x)=x+1), what is the minimum value of ((f-g)(x))?

Explanation opens after your attempt
Correct Answer

A. \(\frac{3}{4}\)

Step 1

Concept

((f-g)(x)=x-2+x+1=\left\(x+\frac{1}{2}\right\)2+\frac{3}{4}). Therefore the minimum is \(\frac{3}{4}\).

Step 2

Why this answer is correct

The correct answer is A. \(\frac{3}{4}\). ((f-g)(x)=x-2+x+1=\left\(x+\frac{1}{2}\right\)2+\frac{3}{4}). Therefore the minimum is \(\frac{3}{4}\).

Step 3

Exam Tip

((f-g)(x)=x-2+x+1=\left\(x+\frac{1}{2}\right\)2+\frac{3}{4})। इसलिए न्यूनतम \(\frac{3}{4}\) है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=x-2+2x+2) और (g(x)=x+1) हैं, तो ((f-g)(x)) का न्यूनतम मान क्या होगा? / If (f(x)=x-2+2x+2) and (g(x)=x+1), what is the minimum value of ((f-g)(x))?

Correct Answer: A. \(\frac{3}{4}\). Explanation: ((f-g)(x)=x-2+x+1=\left\(x+\frac{1}{2}\right\)2+\frac{3}{4})। इसलिए न्यूनतम \(\frac{3}{4}\) है। / ((f-g)(x)=x-2+x+1=\left\(x+\frac{1}{2}\right\)2+\frac{3}{4}). Therefore the minimum is \(\frac{3}{4}\).

Which concept should I revise for this Mathematics MCQ?

((f-g)(x)=x-2+x+1=\left\(x+\frac{1}{2}\right\)2+\frac{3}{4}). Therefore the minimum is \(\frac{3}{4}\).

What exam hint can help solve this Mathematics question?

((f-g)(x)=x-2+x+1=\left\(x+\frac{1}{2}\right\)2+\frac{3}{4})। इसलिए न्यूनतम \(\frac{3}{4}\) है।