यदि (f(x)=\sqrt{x-2-36}) है, तो (f(-10)) क्या है?
If (f(x)=\sqrt{x-2-36}), what is (f(-10))?
Explanation opens after your attempt
A. (8)
Concept
(f(-10)=\sqrt{100-36}=\sqrt{64}=8). In exams the principal value of the square root is non-negative.
Why this answer is correct
The correct answer is A. (8). (f(-10)=\sqrt{100-36}=\sqrt{64}=8). In exams the principal value of the square root is non-negative.
Exam Tip
(f(-10)=\sqrt{100-36}=\sqrt{64}=8) है। परीक्षा में वर्गमूल की principal value non-negative होती है।
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