यदि (f(x)=\sqrt{x-2-36}) है, तो (f(-10)) क्या है?

If (f(x)=\sqrt{x-2-36}), what is (f(-10))?

Explanation opens after your attempt
Correct Answer

A. (8)

Step 1

Concept

(f(-10)=\sqrt{100-36}=\sqrt{64}=8). In exams the principal value of the square root is non-negative.

Step 2

Why this answer is correct

The correct answer is A. (8). (f(-10)=\sqrt{100-36}=\sqrt{64}=8). In exams the principal value of the square root is non-negative.

Step 3

Exam Tip

(f(-10)=\sqrt{100-36}=\sqrt{64}=8) है। परीक्षा में वर्गमूल की principal value non-negative होती है।

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यदि (f(x)=\sqrt{x-2-36}) है, तो (f(-10)) क्या है? / If (f(x)=\sqrt{x-2-36}), what is (f(-10))?

Correct Answer: A. (8). Explanation: (f(-10)=\sqrt{100-36}=\sqrt{64}=8) है। परीक्षा में वर्गमूल की principal value non-negative होती है। / (f(-10)=\sqrt{100-36}=\sqrt{64}=8). In exams the principal value of the square root is non-negative.

Which concept should I revise for this Mathematics MCQ?

(f(-10)=\sqrt{100-36}=\sqrt{64}=8). In exams the principal value of the square root is non-negative.

What exam hint can help solve this Mathematics question?

(f(-10)=\sqrt{100-36}=\sqrt{64}=8) है। परीक्षा में वर्गमूल की principal value non-negative होती है।