यदि (f(x)=\sqrt{x-1}) और (g(x)=x-3) हों, तो (\left\(\frac{g}{f}\right\)(x)) का प्रांत क्या होगा?

If (f(x)=\sqrt{x-1}) and (g(x)=x-3), what is the domain of (\left\(\frac{g}{f}\right\)(x))?

Explanation opens after your attempt
Correct Answer

A. ( \(1,\infty\) )

Step 1

Concept

The denominator is \(\sqrt{x-1}\), so (x-1>0). In a quotient, the denominator can never be (0).

Step 2

Why this answer is correct

The correct answer is A. ( \(1,\infty\) ). The denominator is \(\sqrt{x-1}\), so (x-1>0). In a quotient, the denominator can never be (0).

Step 3

Exam Tip

भाजक \(\sqrt{x-1}\) है, इसलिए (x-1>0) होना चाहिए। भागफल में हर कभी (0) नहीं हो सकता।

Question me issue ya doubt hai?

Answer, explanation, typing mistake ya suggestion directly hamari team ko bhejein. 📱Helpline (Call / WhatsApp): +91 7272824365

Related Mathematics Questions

FAQs

Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{x-1}) और (g(x)=x-3) हों, तो (\left\(\frac{g}{f}\right\)(x)) का प्रांत क्या होगा? / If (f(x)=\sqrt{x-1}) and (g(x)=x-3), what is the domain of (\left\(\frac{g}{f}\right\)(x))?

Correct Answer: A. ( \(1,\infty\) ). Explanation: भाजक \(\sqrt{x-1}\) है, इसलिए (x-1>0) होना चाहिए। भागफल में हर कभी (0) नहीं हो सकता। / The denominator is \(\sqrt{x-1}\), so (x-1>0). In a quotient, the denominator can never be (0).

Which concept should I revise for this Mathematics MCQ?

The denominator is \(\sqrt{x-1}\), so (x-1>0). In a quotient, the denominator can never be (0).

What exam hint can help solve this Mathematics question?

भाजक \(\sqrt{x-1}\) है, इसलिए (x-1>0) होना चाहिए। भागफल में हर कभी (0) नहीं हो सकता।