यदि (f(x)=\sqrt{\frac{x-1}{x+2}}), तो प्रांत कौन सा है?
If (f(x)=\sqrt{\frac{x-1}{x+2}}), which is the domain?
Explanation opens after your attempt
Correct Answer
A. (\(-\infty,-2\)\cup[1,\infty))
Concept
The condition is \(\frac{x-1}{x+2}\ge 0\) and \(x\ne -2\). A sign chart gives (\(-\infty,-2\)\cup[1,\infty)).
Why this answer is correct
The correct answer is A. (\(-\infty,-2\)\cup[1,\infty)). The condition is \(\frac{x-1}{x+2}\ge 0\) and \(x\ne -2\). A sign chart gives (\(-\infty,-2\)\cup[1,\infty)).
Exam Tip
शर्त \(\frac{x-1}{x+2}\ge 0\) और \(x\ne -2\) है। साइन चार्ट से (\(-\infty,-2\)\cup[1,\infty)) मिलता है।
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