यदि (f(x)=\sqrt{9-x-2}) और (g(x)=\frac{1}{x}) हों, तो ((f+g)(x)) का प्रांत क्या होगा?

If (f(x)=\sqrt{9-x-2}) and (g(x)=\frac{1}{x}), what is the domain of ((f+g)(x))?

Explanation opens after your attempt
Correct Answer

A. \( [-3,3]\setminus{0} \)

Step 1

Concept

The root needs \(9-x^2\ge 0\), so \(x\in[-3,3]\), and \(x\ne 0\). The domain of the sum is the intersection.

Step 2

Why this answer is correct

The correct answer is A. \( [-3,3]\setminus{0} \). The root needs \(9-x^2\ge 0\), so \(x\in[-3,3]\), and \(x\ne 0\). The domain of the sum is the intersection.

Step 3

Exam Tip

मूल के लिए \(9-x^2\ge 0\), इसलिए \(x\in[-3,3]\), और \(x\ne 0\)। योग का प्रांत दोनों शर्तों का प्रतिच्छेद है।

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Mathematics Answer, Explanation and Revision Hints

यदि (f(x)=\sqrt{9-x-2}) और (g(x)=\frac{1}{x}) हों, तो ((f+g)(x)) का प्रांत क्या होगा? / If (f(x)=\sqrt{9-x-2}) and (g(x)=\frac{1}{x}), what is the domain of ((f+g)(x))?

Correct Answer: A. \( [-3,3]\setminus{0} \). Explanation: मूल के लिए \(9-x^2\ge 0\), इसलिए \(x\in[-3,3]\), और \(x\ne 0\)। योग का प्रांत दोनों शर्तों का प्रतिच्छेद है। / The root needs \(9-x^2\ge 0\), so \(x\in[-3,3]\), and \(x\ne 0\). The domain of the sum is the intersection.

Which concept should I revise for this Mathematics MCQ?

The root needs \(9-x^2\ge 0\), so \(x\in[-3,3]\), and \(x\ne 0\). The domain of the sum is the intersection.

What exam hint can help solve this Mathematics question?

मूल के लिए \(9-x^2\ge 0\), इसलिए \(x\in[-3,3]\), और \(x\ne 0\)। योग का प्रांत दोनों शर्तों का प्रतिच्छेद है।