यदि (f(x)=\sqrt{9-x-2}) और (g(x)=\frac{1}{x}) हों, तो ((f+g)(x)) का प्रांत क्या होगा?
If (f(x)=\sqrt{9-x-2}) and (g(x)=\frac{1}{x}), what is the domain of ((f+g)(x))?
Explanation opens after your attempt
A. \( [-3,3]\setminus{0} \)
Concept
The root needs \(9-x^2\ge 0\), so \(x\in[-3,3]\), and \(x\ne 0\). The domain of the sum is the intersection.
Why this answer is correct
The correct answer is A. \( [-3,3]\setminus{0} \). The root needs \(9-x^2\ge 0\), so \(x\in[-3,3]\), and \(x\ne 0\). The domain of the sum is the intersection.
Exam Tip
मूल के लिए \(9-x^2\ge 0\), इसलिए \(x\in[-3,3]\), और \(x\ne 0\)। योग का प्रांत दोनों शर्तों का प्रतिच्छेद है।
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