यदि (f(x)=\frac{x}{x-2}) और (g(x)=\frac{2}{x-2}) हैं, तो ((f-g)(x)) किसके बराबर है और उसका प्रांत क्या है?
If (f(x)=\frac{x}{x-2}) and (g(x)=\frac{2}{x-2}), what is ((f-g)(x)) and its domain?
Explanation opens after your attempt
A. (1), \(x\ne 2\)
Concept
((f-g)(x)=\frac{x-2}{x-2}=1), but (x=2) is outside the original domain. Keep restrictions even after simplification.
Why this answer is correct
The correct answer is A. (1), \(x\ne 2\). ((f-g)(x)=\frac{x-2}{x-2}=1), but (x=2) is outside the original domain. Keep restrictions even after simplification.
Exam Tip
((f-g)(x)=\frac{x-2}{x-2}=1), पर (x=2) मूल प्रांत से बाहर है। सरलीकरण के बाद भी प्रतिबंध याद रखें।
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