यदि (f(x)=\frac{x-1}{x+2}) और (g(x)=\frac{x+2}{x-1}) हैं, तो (fg) का सही डोमेन क्या है?
If (f(x)=\frac{x-1}{x+2}) and (g(x)=\frac{x+2}{x-1}), what is the correct domain of (fg)?
Explanation opens after your attempt
A. \( \mathbb{R}-{-2,1} \)
Concept
Although (fg=1), the original functions do not allow (x=-2) and (x=1). It is wrong to enlarge the domain after simplification.
Why this answer is correct
The correct answer is A. \( \mathbb{R}-{-2,1} \). Although (fg=1), the original functions do not allow (x=-2) and (x=1). It is wrong to enlarge the domain after simplification.
Exam Tip
यद्यपि (fg=1) बनता है, मूल फलनों में (x=-2) और (x=1) अनुमत नहीं हैं। सरलीकृत अभिव्यक्ति से डोमेन बढ़ाना गलत है।
Login to save your score, XP, coins and progress.
