यदि (f(x)=\frac{x-1}{x+1}) और (g(x)=\frac{x+1}{x-1}) हों, तो ((f-g)(x)) का सरल रूप क्या है?
If (f(x)=\frac{x-1}{x+1}) and (g(x)=\frac{x+1}{x-1}), what is the simplified form of ((f-g)(x))?
Explanation opens after your attempt
A. \(\frac{-4x}{x^2-1},\ x\ne \pm1\)
Concept
The numerator is ((x-1)2-(x+1)2=-4x). Handle the negative sign and square expansion carefully.
Why this answer is correct
The correct answer is A. \(\frac{-4x}{x^2-1},\ x\ne \pm1\). The numerator is ((x-1)2-(x+1)2=-4x). Handle the negative sign and square expansion carefully.
Exam Tip
अंश ((x-1)2-(x+1)2=-4x) है। ऋण चिह्न और वर्ग विस्तार ध्यान से करें।
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