यदि (f(x)=\frac{1}{x+1}) और (g(x)=\frac{1}{x-1}) हों, तो ((f+g)(x)) का सरल रूप क्या है?
If (f(x)=\frac{1}{x+1}) and (g(x)=\frac{1}{x-1}), what is the simplified form of ((f+g)(x))?
Explanation opens after your attempt
Correct Answer
A. \(\frac{2x}{x^2-1},\ x\ne \pm1\)
Concept
With common denominator ((x+1)(x-1)), the numerator is ((x-1)+(x+1)=2x). Do not forget excluded denominator values.
Why this answer is correct
The correct answer is A. \(\frac{2x}{x^2-1},\ x\ne \pm1\). With common denominator ((x+1)(x-1)), the numerator is ((x-1)+(x+1)=2x). Do not forget excluded denominator values.
Exam Tip
समान हर ((x+1)(x-1)) लेने पर अंश ((x-1)+(x+1)=2x) मिलता है। हर के शून्य मान हटाना न भूलें।
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