यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\frac{1}{|x|-2}) से दिया जाए तो सही प्रांत क्या होना चाहिए?

If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=\frac{1}{|x|-2}), what should be the correct domain?

Explanation opens after your attempt
Correct Answer

A. \(\mathbb{R}-{-2,2}\)

Step 1

Concept

The denominator must be non-zero, so \(|x|-2\ne0\) and \(x\ne\pm2\). In modulus denominators check both signs.

Step 2

Why this answer is correct

The correct answer is A. \(\mathbb{R}-{-2,2}\). The denominator must be non-zero, so \(|x|-2\ne0\) and \(x\ne\pm2\). In modulus denominators check both signs.

Step 3

Exam Tip

हर शून्य न हो, इसलिए \(|x|-2\ne0\) और \(x\ne\pm2\) चाहिए। मापांक वाले हर में दोनों चिन्ह जांचें।

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Mathematics Answer, Explanation and Revision Hints

यदि \(f:\mathbb{R}\to\mathbb{R}\) को (f(x)=\frac{1}{|x|-2}) से दिया जाए तो सही प्रांत क्या होना चाहिए? / If \(f:\mathbb{R}\to\mathbb{R}\) is given by (f(x)=\frac{1}{|x|-2}), what should be the correct domain?

Correct Answer: A. \(\mathbb{R}-{-2,2}\). Explanation: हर शून्य न हो, इसलिए \(|x|-2\ne0\) और \(x\ne\pm2\) चाहिए। मापांक वाले हर में दोनों चिन्ह जांचें। / The denominator must be non-zero, so \(|x|-2\ne0\) and \(x\ne\pm2\). In modulus denominators check both signs.

Which concept should I revise for this Mathematics MCQ?

The denominator must be non-zero, so \(|x|-2\ne0\) and \(x\ne\pm2\). In modulus denominators check both signs.

What exam hint can help solve this Mathematics question?

हर शून्य न हो, इसलिए \(|x|-2\ne0\) और \(x\ne\pm2\) चाहिए। मापांक वाले हर में दोनों चिन्ह जांचें।