यदि \(A=\{x:x\}\) संख्या 18 का धनात्मक सम भाजक है(}) और \(B=\{2,6,18\}\), तो कौन सा कथन सत्य है?
If \(A=\{x:x\}\) is a positive even divisor of 18(}) and \(B=\{2,6,18\}\), which statement is true?
Explanation opens after your attempt
Correct Answer
B. (A=B)
Concept
The positive even divisors of 18 are 2, 6 and 18. Checking each condition one by one reduces mistakes in exams.
Why this answer is correct
The correct answer is B. (A=B). The positive even divisors of 18 are 2, 6 and 18. Checking each condition one by one reduces mistakes in exams.
Exam Tip
18 के धनात्मक सम भाजक 2, 6 और 18 हैं। शर्तों को एक-एक करके जांचना परीक्षा में गलती कम करता है।
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