यदि \(A=\{x:x\}\) (18) का धनात्मक भाजक है और (x<10}) तथा \(B=\{1,2,3,6,9\}\) है तो कौन सा कथन सत्य है?
If \(A=\{x:x\}\) is a positive divisor of (18) and (x<10}) and \(B=\{1,2,3,6,9\}\) then which statement is true?
Explanation opens after your attempt
Correct Answer
A. (A=B)
Concept
The positive divisors of (18) less than (10) are (1,2,3,6,9), so (A=B). In exams apply combined conditions together.
Why this answer is correct
The correct answer is A. (A=B). The positive divisors of (18) less than (10) are (1,2,3,6,9), so (A=B). In exams apply combined conditions together.
Exam Tip
(18) के (10) से कम धनात्मक भाजक (1,2,3,6,9) हैं इसलिए (A=B)। परीक्षा में संयुक्त शर्तों को एक साथ लगाएं।
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